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School of Mathematics and Statistics
Carleton University
Math. 69.107

SOLUTIONS TO OLD TEST 3

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This test is out of a Total of 30.

PART I: Multiple Choice Questions
(Choose and CIRCLE only ONE answer)

  1. [2 marks] Which of the following expressions gives the area of the region bounded by the curves tex2html_wrap_inline194 y = -x , and between the lines x=1 and x=4?

    (a) tex2html_wrap_inline202

    (b) tex2html_wrap_inline204

    (c) tex2html_wrap_inline206

    tex2html_wrap294 tex2html_wrap_inline208

  2. [2 marks] Evaluate the improper integral tex2html_wrap_inline210 .

    (a) tex2html_wrap296

    (b) tex2html_wrap_inline212

    (c) tex2html_wrap_inline214

    (d) tex2html_wrap_inline216 .

  3. [2 marks] Which of the following expressions gives the volume of the solid of revolution obtained when the region bounded by the graphs of y = 2x and tex2html_wrap_inline220 is revolved about the y-axis?

    (a) tex2html_wrap_inline224

    tex2html_wrap298 tex2html_wrap_inline226

    (c) tex2html_wrap_inline228

    (d) tex2html_wrap_inline230

  4. [2 marks] Evaluate tex2html_wrap_inline232

    (a) tex2html_wrap_inline234

    (b) tex2html_wrap_inline236

    tex2html_wrap300 tex2html_wrap_inline238

    (d) tex2html_wrap_inline240

    tex2html_wrap_inline242 Use a trig. identity and a substitution

  5. [2 marks] Answer TRUE or FALSE:

    The value of the improper integral tex2html_wrap_inline244 is given by I = 1

    tex2html_wrap302 , (b) FALSE

PART II: Show all work here.
No additional pages will be accepted

  1. [5+5 marks] Evaluate the following integrals using any method:

    a) tex2html_wrap_inline248 .

    Solution: Let tex2html_wrap_inline250 . Then tex2html_wrap_inline252 . When x=0, u=0 and when tex2html_wrap_inline258 , u=0. and so

    eqnarray74

    Alternately,

    eqnarray82

    Thus,

    eqnarray88

    b) Evaluate tex2html_wrap_inline262

    Use the Table Method:

    tabular98

    and the final answer can be written as,

    eqnarray109

  2. Evaluate the following integrals using any method.

    [4 marks] (a) tex2html_wrap_inline276

    Solution: Write

    displaymath278

    Integrate by Parts twice or use the "MYCAR" trick! You'll get

    displaymath280

    where the entry in the Box is given by tex2html_wrap_inline282 . See Section 8.3.4 for details. This I is an antiderivative, and so

    displaymath284

    [4 marks] (b) tex2html_wrap_inline286

    Solution: The degree of the numerator exceeds that of the denominator and so we must divide these expressions. Thus

    displaymath288

    Next, we use partial fractions on the third integral thus:

    eqnarray145

    where we let tex2html_wrap_inline290 , tex2html_wrap_inline292 , in the second integral (and didn't have to use partial fractions).




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Next: About this document

Angelo Mingarelli
Fri Nov 19 10:38:33 EST 1999